Load dimensions

To obtain an approximate maximum length for the glide beam the 4m travelling distance needs to be taken account of along with any other clearances for load and shoulder joints total approx 290mm.



For the worst case scenarios of loading conditions, the two most probable loads (rubble) include reinforced concrete and steel I beams.

Using the BS 5950 standards, [Limit State Design of Reinforced Concrete By B. C. Punmia, Arun Kumar Jain, Arun Kr. Jain, Ashok Kr. Jain] to find common dimension sized beams e.g.



Approximate steel: concrete ratio would need to be estimated to calculate volumes, and the missing Z dimension. Based on several different pre-stressed processes, wire dimensions...

Processes from [Limit State Design of Reinforced Concrete By B. C. Punmia, Arun Kumar Jain, Arun Kr. Jain, Ashok Kr. Jain]:








Approximate dimensions sizes were hence obtained:



The final ‘z’ dimension would need to be calculated. The following parameters are taken into account:



Calculations of dimensions to give a load of approximately 1 tonne:

Steel

5% of the cross sectional area =0.0045m^2
Assume Z=4m to obtain volume for the following equation:
Mass = Volume * Density
Mass= (0.0045*4)m^3*(7800) kg/m^3
Mass=140.4kg

Concrete

95% of the cross sectional area=0.0855m^2
Assume Z=4m to obtain volume for the following equation:
Mass = Volume * Density
Mass= (0.0855m *4)m^3*(2400) kg/m^3
Mass=820.8kg

Total mass = 140.4kg + 820.8kg= 961.2kg

In order to obtain the desired mass approximately a 4% increase in length would be required, hence obtaining:

Steel

5% of the cross sectional area =0.0045m^2
Assume Z=4.16m to obtain volume for the following equation:
Mass = Volume * Density
Mass= (0.0045*4.16)m^3*(7800) kg/m^3
Mass=146.016kg

Concrete

95% of the cross sectional area=0.0855m^2
Assume Z=4.16m to obtain volume for the following equation:
Mass = Volume * Density
Mass= (0.0855m *4.16)m^3*(2400) kg/m^3
Mass=853.632kg

Total mass = 146.016kg + 853.632kg = 999.648kg

Hence the length Z required of the load that would need to be lifted is approx 4.16m.

Another possibility is to find several shorter sections and hoist them together or one wider section with the following dimensions:



Z would be approximately 2m.

Steel I beams

The following data was obtained from http://www.engineeringtoolbox.com/british-universal-steel-columns-beams-d_1316.html:




A standard I beam was selected for the worst scenario load that could be found and require lifting (this particular beam was selected as it poses the greatest load risk as it could potentially surpass the 1 tonne requirement)
Calculate Z length
1000kg/238.1 kg/m = 4.19m (length that would need to be found to pose issues to the crane)

From these calculations a total clearance of approximately 300 -400mm may be required to be able to lift most available loads safely from a to b.
It will be assumed that these loads will be lifted from their midsection (centre of gravity) to maintain safety.



Another issue which would need to be addressed is the following: